如何在Mysql中实现复制检查脚本

#!/usr/bin/env bash
base_dir="/home/mysql/mysql-5.7.20-linux-glibc2.12-x86_64"
mysql_host="10.1 .1.1"
mysql_user="bkp_user"
mysql_psw="password"
mysql_port="3306"
function get_v()
{
if test - f /tmp/mysql_slave.txt;然后
# for ((i=1;i<6;i++));
# args$i=`awk -v i=$1 'NR==i {print $NF}' /tmp/mysql_slave.txt`
case $1 in
1)
args1=`awk 'NR==1 {print $NF}' /tmp/mysql_slave. txt`
;;
2)
args2=`awk 'NR==2 {print $NF}' /tmp/mysql_slave.txt`
;;
3)
args3=`awk 'NR==3 {print $NF}' /tmp/mysql_slave.txt`
;;
4)
args4=`awk 'NR==4 {print $NF}' /tmp/mysql_slave.txt`
;;
5)
args5=`awk 'NR==5 {print $NF}' /tmp/mysql_slave.txt`
;;
*)
echo "usag: sh $0 1~5"
esac
# done
else
echo "出现错误！"
exit 0
fi
}
$base_dir/bin/mysql -h$mysql_host -u$mysql_user -p$mysql_psw -Pmysql_port -e '显示从属状态\G;' |egrep 'Read_Master_Log_Pos|Exec_Master_Log_Pos|Master_Log_File|Relay_Master_Log_File|Seconds_Behind_Master' >/tmp/mysql_s lave .txt
for ((i=1;i<6;i++)); do
get_v $i
done

if [ $args1 == $args3 - a $args2 == $args4 ];然后
echo“从机状态正常！”
else
printf "落后master的秒数: $args5\n"
printf "+%13s+%11s+\n" ----------- -- --- --------
printf "|%13s|%11s|\n+------------------------+-------- ---+\ n" $args1 $args2
printf "|%13s|%11s|\n+-------------+---------- -+\n" $args3 $args4
fi

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